# How do you find the vertex for #y = x^2 - 2x#?

The vertex is at

If we put the quadratic function in vertex form, we can locate its vertex with relative ease:

This indicates that our quadratic function's vertex form is:

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To find the vertex of the parabola represented by the equation y = x^2 - 2x, you can use the formula x = -b / 2a, where a is the coefficient of the x^2 term and b is the coefficient of the x term. In this case, a = 1 and b = -2. Plug these values into the formula to get x = -(-2) / (2*1) = 1. So, the x-coordinate of the vertex is 1. To find the y-coordinate, substitute x = 1 back into the equation: y = 1^2 - 2*1 = 1 - 2 = -1. Therefore, the vertex of the parabola is (1, -1).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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